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40n^2-285n-280=0
a = 40; b = -285; c = -280;
Δ = b2-4ac
Δ = -2852-4·40·(-280)
Δ = 126025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{126025}=355$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-285)-355}{2*40}=\frac{-70}{80} =-7/8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-285)+355}{2*40}=\frac{640}{80} =8 $
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